C PROGRAM: Program to read the name, address, and salary of 5 employees using array of structure. Display information of each employee and find the average salary on C language - Sparsh Blog

 Ans:-

Program to read the name, address, and salary of 5 employees using array of structure. Display information of each employee and find the average salary on C language.

Program is as follows:--

#include<stdio.h>

#include<string.h>

struct employee

{

        char name[10];

        char address[50];

        int salary;

};

void main()

{

        int i, total=0, Avg;

        struct employee st[5];

        printf("Enter Records of 5 Employees");

        for(i=0;i<5;i++)

        {

                printf("\nEnter Name:");

                scanf("%s",st[i].name);

                printf("\nEnter Address:");

                scanf("%s",st[i].address);

                printf("\nEnter Salary");

                scanf("%d",&st[i].salary);

                total = total + st[i].salary;

        }

        Avg = total/5;

        printf("\n Employee Information List:-");

        for(i=0;i<5;i++)

        {

                printf("\n Name:%s , Address:%s,Salary:%d",st[i].name,st[i].address, st[i].salary);

        }

        printf("\n Average Salary:%d", Avg);

}

OUTPUT:---

Enter Records of 5 Employees

Enter Name : Vijay

Enter Address : 1B/35

Enter Salay : 2000 

Enter Name : tony

Enter Address : 5F/76

Enter Salary : 15000

Enter Name : Sahil

Enter Address : 1C/89

Enter Salary : 45000

Enter Name : Puneet

Enter Address : 4C/32

Enter Salary : 10000

Enter Name : Rishabh

Enter Address : 5C/55

Enter Salary : 13000

Employee Information List:-

Name : Vijay , Address : 1B/35 , Salary : 2000

Name : Tony , Address : 5F/76 , Salary : 15000

Name :Sahil , Address : 1C/89 , Salary : 45000

Name : Puneet , Address : 4C/32 , Salary : 10000

Name : Rishabh , Address : 5C/55 , Salary : 13000

Average Salary : 17000

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